In short circuit transfer, increasing the inductance does what?

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Multiple Choice

In short circuit transfer, increasing the inductance does what?

Explanation:
Inductors resist sudden changes in current, so during a short-circuit event the current would like to rise quickly, but a larger inductance slows that rise. The rate at which current can increase through an inductor is proportional to the voltage across it and inversely proportional to its inductance (di/dt ≈ V/L). When L is bigger, di/dt is smaller, so the current climbs more slowly after the short appears. That’s why increasing inductance slows the rate of current rise when the short is produced. It doesn’t inherently make heat appear more, and it doesn’t cause a faster rise or no effect—the inductor’s opposition to changing current is what changes with inductance.

Inductors resist sudden changes in current, so during a short-circuit event the current would like to rise quickly, but a larger inductance slows that rise. The rate at which current can increase through an inductor is proportional to the voltage across it and inversely proportional to its inductance (di/dt ≈ V/L). When L is bigger, di/dt is smaller, so the current climbs more slowly after the short appears. That’s why increasing inductance slows the rate of current rise when the short is produced. It doesn’t inherently make heat appear more, and it doesn’t cause a faster rise or no effect—the inductor’s opposition to changing current is what changes with inductance.

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